Sunday, January 17, 2010

In a dihybrid cross between a parent that is a double heterozygote (AaBb) and a parent that is homozygous?

recessive (aabb), how many different phenotypes will there be in their offspring. List the specific amounts. If you can put a Punnet Square in that would be great!In a dihybrid cross between a parent that is a double heterozygote (AaBb) and a parent that is homozygous?
The possible gamete genotypes of the heterozygote are: AB, Ab, aB, ab


The possible gamete genotypes of the homozygous recessive are: ab





If these are crossed (I have done a punnet square - see the link below) you end up with: 25% AaBb, 25% Aabb, 25% aaBb, 25% aabb





Which means there are four different offspring phenotypes, with equal amounts of each.





Punnet square: http://i90.photobucket.com/albums/k270/h鈥?/a>





Hope this helps!

No comments:

Post a Comment